The equation $y = 4$ , can be mentioned in the form of two variable linear equation as,

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$0 \cdot x + 4 \cdot y = 4$

$0 \cdot x + 1 \cdot y = 1$

$0 \cdot x + 1 \cdot y = 4$

$0 \cdot x + 4 \cdot y = 1$

answer is C.

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Detailed Solution

The linear equation in form of two variables is given as, $a x + b y + c = 0$ .

Given, y = 4

Equation: $0 \cdot x + 4 \cdot y = 4$
Putting the value of y in the equation, we get,
0 + 4 x 4 = 4
16 $\neq$ 4
Therefore, $0 \cdot x + 4 \cdot y = 4$ is not the correct equation.

Equation: $0 \cdot x + 1 \cdot y = 1$
Putting the value of y in the equation, we get,
0 + 1 x 4 = 1
4 $\neq$ 1
Therefore, $0 \cdot x + 1 \cdot y = 1$ is not the correct equation.

Equation: $0 \cdot x + 1 \cdot y = 4$
Putting the value of y in the equation, we get,
0 + 1 x 4 = 4
4 = 4
Therefore, $0 \cdot x + 1 \cdot y = 4$ is the correct equation.

Equation: $0 \cdot x + 4 \cdot y = 1$
Putting the value of y in the equation, we get,
0 + 4 x 4 = 1
16 $\neq$ 1
Therefore, $0 \cdot x + 4 \cdot y = 1$ is not the correct equation.