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Q.

The equation zz+(2-3i)z+(2+3i)z¯+4=0 represents a circle of radius

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a

2

b

6

c

3

d

4

answer is B.

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Detailed Solution

z z+(2-3i)z+(2+3i) z+4=0 (x+iy) (x-iy)+(2-3i) (x+iy)+(2+3i) (x-iy)+4=0 x2+y2+2x+3y+2x+3y+4=0 x2+y2+4x+6y+4=0 r=4+9-4=3 

 General equation of circle  is   zz¯+az¯+a¯z+b=0.  centre =a & radius =|a|2b

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