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The equilibrium constant at 298 K for a reaction, $A + B \overset{}{⇌} C + D$ is 100. If the initial concentrations of all the four species were 1 M each, then equilibrium concentration of $D (i n m o l L^{- 1})$ will be

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1.818

0.818

1.182

0.182

answer is B.

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Detailed Solution

$A + B ⇌ C + D 1 - x 1 - x 1 + x 1 + x 100 = \frac{(1 + x)^{2}}{(1 - x)^{2}} \frac{1 + x}{1 - x} = 10 1 + x = 10 - 10 x 11 x = 9 x = \frac{9}{11} [D] = 1 + x = 1 + \frac{9}{11} = \frac{20}{11} = 1.818$

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