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The equilibrium constant for the reaction HI(g)12H2(g)+12I2(g)  is 7.4. The value of equilibrium constant of the reaction 2HI(g)H2(g)+I2(g) will be

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a
7.4
b
1/7.4
c
54.76
d
7.4

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detailed solution

Correct option is C

Knew =Kold 2=7.422=54.76

A number that represents the proportionality of the reactant and product concentrations at equilibrium in a reversible chemical reaction at a certain temperature.

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