The equilibrium constant for the reversible reaction, N2 + 3H2 ⇌ 2NH3 is K and for the reaction 12N2 + 32H2 ⇌ NH3 the equilibrium constant is K'. K and K' will be related as

K'=Kn; Hence n=12 ∴ K'=K1/2=K

The equilibrium constant for the reversible reaction, N2 + 3H2 ⇌ 2NH3 is K and for the reaction 12N2 + 32H2 ⇌ NH3 the equilibrium constant is K'. K and K' will be related as

K'=Kn; Hence n=12 ∴ K'=K1/2=K

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The equilibrium constant for the reversible reaction, $N_{2} + 3 H_{2} ⇌ 2 {NH}_{3}$ is K and for the reaction $\frac{1}{2} N_{2} + \frac{3}{2} H_{2} ⇌ {NH}_{3}$ the equilibrium constant is $K' . K and K'$ will be related as

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$K = K'$

$K' = \sqrt{K}$

$K = \sqrt{K'}$

$K \times K' = 1$

answer is B.

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$K' = K^{n}; Hence n = \frac{1}{2} ∴ K' = K^{1 / 2} = \sqrt{K}$

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The equilibrium constant for the reversible reaction, N2 + 3H2 ⇌ 2NH3 is K and for the reaction 12N2 + 32H2 ⇌ NH3 the equilibrium constant is K'. K and K' will be related as

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The equilibrium constant for the reversible reaction, $N_{2} + 3 H_{2} ⇌ 2 {NH}_{3}$ is K and for the reaction $\frac{1}{2} N_{2} + \frac{3}{2} H_{2} ⇌ {NH}_{3}$ the equilibrium constant is $K' . K and K'$ will be related as