The equilibrium constants of a reaction at 298 K and 308 K are 1.0 × 10−2 and 2 ×10−2 Respectively, the reaction is

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The equilibrium constants of a reaction at 298 K and 308 K are $1.0 \times 10^{- 2}$ and $2 \times 10^{- 2}$ Respectively, the reaction is

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Exothermic

Endothermic

May be endothermic or exothermic

Cannot be predicted

answer is B.

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Detailed Solution

Increase in temperate, $K_{C}$ value is increased, means reaction is endothermic.

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