The equilibrium of the reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$   is set up at 300 K by mixing  $N_2\left(g\right)and{H}_2\left(g\right)$.The standard free energy of formation of  $N{H}_3\left(g\right)$  is -15.53 kJ/mol. If after one hour of mixing the partial pressure of  $N_2,H_{2}andN{H}_3$, are 50, 2 and 200 bar respectively and the enthalpy change of reaction is -4.2 kJ, what is the entropy change of the reaction.  $\left(inJ{K}^{-1}\right)[Given:\mathcal{l}n100=4.6,RT=2500J]$