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Q.

The equilibrium pressure of NH4CN(S)NH3(g)+HCN(g) is 4 atm. In an experiment, if NH4CNs is allowed to decompose in presence of NH3 at 3 atm, then

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a

pressure of HCN = 1atm (at new equilibrium state)

b

pressure of NH3=4 atm (at new equilibrium state)

c

pressure of HCN = 2atm (at old equilibrium state)

d

Kp = 4

answer is A, B, C, D.

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Detailed Solution

NH4CN(s)NH3(g)+HCN(g)

At equilibria :                          (3 + 1)atm         1atm

 Kp=PNH3×PHCN

=4×1=4

PHCN=1

PNH3=4

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