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The equilibrium reaction $A {⇌ B}_{k_{b}}^{k_{f}}$ is started with A such that initially one can write $A \overset{k_{i}^{'}}{⟶} B$ In such a case, which of the following will be true?

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$k_{f} = k_{f}^{'}$

$k_{f} > k_{f}^{'}$

$k_{f} < k_{f}^{'}$

$k_{f}$ may be greater or smaller than Kr depending upon the concentration of A. Thus,

answer is A.

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Detailed Solution

$k_{f}$ does not depend upon the concentration of A.

$k_{f} = k_{f}^{'}$

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