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The equilibrium $N_{2} + O_{2} ⇌ 2 NO$ established in a reaction vessel of $2.5 L$ capacity. The amounts of $N_{2}$ and $O_{2}$ taken at the start were respectively 2 moles and 4 moles. Half a mole of nitrogen has been used up at equilibrium. The molar concentration of nitric oxide is:

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0.6

0.1

0.2

0.4

answer is B.

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Detailed Solution

$N_{2} + O_{2} ⇄ 2 NO$

$2 - \frac{1}{2} 4 - \frac{1}{2}$ 1

$[NO] = \frac{1}{2.5} = 0.4$

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