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The equivalent capacitance between A and B in the circuit given below, is:

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a
2.4μf
b
4.9μf
c
3.6μf
d
5.4μf

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detailed solution

Correct option is A

Combination of capacitors in series and parallel.

C1=5+5+2=12 μF C2=4+2=6 μF 1/CEq=1/6+1/12+1/6=5/12 CEq=2.4 μF

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