The equivalent capacitance between A and B in the circuit given below is:

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4.9µF

3.6µF

5.4µF

2.4µF

answer is D.

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Detailed Solution

Concept: For solving this question, we need to make sure that the simplified diagram of the circuit is correct. We can determine the parallel connections and the series connections using the simplified circuit as a guide.
In the end, this will result in the formation of the circuit's equivalent capacitance. The following formulae must be kept in mind before we can proceed with the question's answer. Here they are:
Equivalent capacitance of the series circuit is denoted by C series
We should know that, C in series =

\frac{1}{\sum_{i = 1}^{n} \frac{1}{c_{i}}}

Equivalent capacitance of the parallel circuit is denoted by C parallel
We should know that, C in parallel =

\sum_{i = 1}^{n} c_{i^{}}

Let's now depict the circuit's streamlined structure. We can draw it like the one shown below for ease in calculation.
Question Image

As a result, we may calculate that the equivalent capacitance is
Equivalent Capacitance = 5 + 5 + 2 = 12 μ F
According to the circuit schematic above, this is the equivalent capacitance of the capacitor bank in the center of the circuit.
Equivalent Capacitance = 4 + 2 = 8 μ F
This is the equivalent capacitance of the capacitor bank in the right end of the circuit as drawn above.
Question Image

∴ Parallel connection of all the series equivalent capacitors rounds up to a total of
Equivalent Capacitance = 2.4 μ F
Hence, the correct option is 4.

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