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Q.

The equivalent capacitance between points A and B in below shown figure will be _____ $μF$ .

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answer is 6.

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Detailed Solution

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Two capacitors are short circuited

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Finally equivalent capacitance

$= \frac{24 x 8}{24 + 8} = \frac{24 x 8}{32} = 6 μF$

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The equivalent capacitance between points A and B in below shown figure will be _____ μF.