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Q.

The equivalent capacitance CAB of the circuit shown in the figure is

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a

2C

b

C

c

45C

d

54C

answer is A.

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Detailed Solution

Correct Answer: Option (A)

Observe symmetry:

The circuit is symmetrical about the center.

Each capacitor has value C.

Redraw & simplify:

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Due to symmetry, use series and parallel combinations to simplify.

Between points A and B, you can simplify the network gradually.

Use Wheatstone Bridge Rule (for capacitors):

In a balanced Wheatstone Bridge, the capacitor in the middle does not carry any charge, so it can be removed from the circuit.

This circuit is a symmetrical bridge, hence the middle capacitor (between diagonals) can be ignored.

When you remove the middle capacitor (using symmetry/Wheatstone Bridge idea), the rest becomes easier to simplify.

After simplification, the total capacitance becomes:

CAB = 2C
Final Answer: Option (A) 2C

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