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Q.

The equivalent capacity of four identical capacitors is 12µF when they are connected in parallel and a potential of 400V is applied. If they are connected in series and same potential is applied then change in energy stored in the system is

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a

40 × 10–3 J

b

90 × 10–2 J

c

48 × 10–2 J

d

20 × 10–2 J

answer is A.

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Detailed Solution

E1=12CPV2=12×12×10−6×(400)2E2=12CSV2=12×34×10−6×(400)2ΔE=12×16×104×454×10−6=0.9J

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