The equivalent capacity of four identical capacitors is 12µF when they are connected in parallel and a potential of 400V is applied. If they are connected in series and same potential is applied then change in energy stored in the system is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

40 × 10^–3 J

90 × 10^–2 J

48 × 10^–2 J

20 × 10^–2 J

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{array}{l} E_{1} = \frac{1}{2} C_{P} V^{2} = \frac{1}{2} \times 12 \times 10^{- 6} \times (400)^{2} \\ E_{2} = \frac{1}{2} C_{S} V^{2} = \frac{1}{2} \times \frac{3}{4} \times 10^{- 6} \times (400)^{2} \\ ΔE = \frac{1}{2} \times 16 \times 10^{4} \times \frac{45}{4} \times 10^{- 6} = 0 .9 J \end{array}$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th