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The equivalent conductances of two strong electrolytes at infinite dilution in H₂O (where ions move freely through a solution) at 25⁰C are given below
$λ_{{CH}_{3} COONa}^{°} =$ 91.0 S cm²/equiv; $λ_{HCl}^{°} =$ 426.2 S cm2 /equiv
What additional information / quantity one needs to calculate $λ^{°}$ of an aqueous solution of acetic acid ?

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$λ_{NaCl}^{°}$

$λ_{H^{+}}^{°}$

$λ_{{ClCH}_{2} COOH}^{°}$

$λ_{{CH}_{3} COOK}^{°}$

answer is A.

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Detailed Solution

$lambda _{C{H_3}COONa}^{eq} + lambda _{HCl}^{eq} = lambda _{C{H_3}CO{O^ - }}^{eq} + lambda _{N{a^ + }}^{eq} + lambda _{{H^ + }}^{eq} + lambda _{C{l^ - }}^{eq} = lambda _{C{H_3}COOH}^{eq} + lambda _{NaCl}^{eq}$

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