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The equivalent conductivity of 0.1 N CH3COOH at 25°C is 80 and at infinite dilution is 400 ohm cm2eq–1. The degree of dissociation of CH3COOH is n ×10-y. "n" value is __________

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answer is 2.

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Detailed Solution

α=ΛvΛ∞=80400=0.2=2×10-1

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The equivalent conductivity of 0.1 N CH3COOH at 25°C is 80 and at infinite dilution is 400 ohm cm2eq–1. The degree of dissociation of CH3COOH is n ×10-y. "n" value is __________