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Q.

The equivalent conductivity of 0.1N CH₃COOH at 25⁰C is 80 and at infinite dilution is 400 ohm^–1. The degree of dissociation of CH₃COOH is

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a

0.1

b

1

c

0.2

d

0.5

answer is B.

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Detailed Solution

$α = \frac{λ_{eq}^{c}}{λ_{eq}^{\infty}} = \frac{80}{400} = 0.2$

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