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The equivalent conductivity of a solution containing 2.54 g of ${CuSO}_{4}$ per litre is ${91.0}^{- 1} Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . Its conductivity would be

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$1.45 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}$

$2.17 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}$

$2.90 \times 10^{- 3} Ω^{- 1} {cm}^{2}$

$2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}$

answer is D.

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Detailed Solution

$κ = Λ_{eq} c = (91.0 Ω^{- 1} {cm}^{2} {eq}^{- 1}) [\frac{2.54}{(159 / 2) \times 1000} eq {cm}^{- 3}] = 2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}$

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