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The equivalent inductance of two inductors is 2.4 H when connected in parallel and 10 H when connected in series. What is the value of inductance of the individual inductors?

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$L_{1} = 5 H, L_{2} = 5 H$

$L_{1} = 6 H, L_{2} = 4 H$

None

$L_{1} = 2 H, L_{2} = 8 H$

answer is A.

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Detailed Solution

When connected in series,
$\begin{aligned} L_{e q} = L_{1} + L_{2} \\ 10 = L_{1} + L_{2} \end{aligned}$

When connected in parallel,

$\begin{array}{l} L_{e q} = \frac{L_{1} L_{2}}{L_{1} + L_{2}} \\ \Rightarrow 2.4 = \frac{L_{1} L_{2}}{L_{1} + L_{2}} \end{array}$

After solving, $L_{1} = 6 H, L_{2} = 4 H$

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