The equivalent mass of an element is 4. Its chloride has vapor density 59.25. Then the valency of the element is

$\mathrm{Let} \mathrm{the} \mathrm{compound} \mathrm{be} {\mathrm{MCl}}_{\mathrm{x}}$

$$\begin{gathered} \mathrm{Molecular} \mathrm{weight} \mathrm{of} {\mathrm{MCl}}_{\mathrm{x}}=2\times \mathrm{Vapour} \mathrm{density} \\ =2\times 59.25=118.5 \end{gathered}$$

$\text{ Equivalent weight }=\frac{\text{ Atomic mass }}{\mathrm{V}\text{alency }}$

$\begin{array}{r}4\mathrm{x}+35.5\mathrm{x}=118.5\\ 39.5\mathrm{x}=118.5\\ \mathrm{x}=\frac{118.5}{39.5}=3\end{array}$