The equivalent resistance of the given circuit between the terminals A and B is

In the given circuit, 5 Ω resistance is shorted. So, it can be discarded.

Now, we get a resolved circuit as shown below

In parallel,

           ${\mathrm{R}}_1=\frac{2\times 2}{2+2}=1\mathrm{\Omega }$

In series,

         ${\mathrm{R}}_2={\mathrm{R}}_1+2=1+2=3\mathrm{\Omega }$

Here, all the three resistances(3Ω) are parallel.

$\therefore$ Equivalent resistance across A and B,

            $\frac{1}{{\mathrm{R}}_{\mathrm{eq}}}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=1\Rightarrow {\mathrm{R}}_{\mathrm{eq}}=1\mathrm{\Omega }$