The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal is

Given, equivalent weight of metal = 9
Vapour density of metal chloride = 59.25
$\therefore$molecular weight of metal chloride
= 2 x V .D = 2 x 59.25 = 118.5
$\therefore \text{ valency of metal }=\frac{\text{ molecular weight of metal chloride }}{\text{ equivalent weight of metal }+35.5}$
$\text{ Valency of metal }=\frac{118.5}{9+35.5}=\frac{118.5}{44.5}=2.66$

Therefore, atomic weight of the metal
= equivalent weight x valency
= 9 x 2.66 = 23.9