The equivalent weight of divalent metal is 32.77. The weight of a single atom is (N₀ = 6.023 x10²³)

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Detailed Solution

EW of metal = 32.77
Valency of metal = 2
Aw of metal = (32.77 x 2)
= 65.4
65.4g of metal contain 6.023 x 10²³ atom
'X, g of metal contain 1 atom
X = 65.4/N_A

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