The equivalent weight of glucose in the reaction C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O is (M is molecular weight)

${\stackrel{0}{\mathrm{C}}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6 + 6{\mathrm{O}}_2 \to 6\stackrel{+4}{\mathrm{C}}{\mathrm{O}}_2 + 6{\mathrm{H}}_2\mathrm{O}$

As there are six molecules of CO2, hence valence electrons (n-factor) becomes 24 and equivalent weight is M/24.