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Q.

The equivalent weight of hypo in the reaction [M = molecular weight]
2Na2S2O3 + I2 → 2NaI + Na2S4O6 is

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a

M

b

M/4

c

M/3

d

M/2

answer is A.

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Detailed Solution

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2Na2S-22O3+I2→2NaI+Na2S2.54O6 n-factor of Na2S2O3=22.5-2=1

Equivalent weight is M/1.

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