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Q.

The equivalent weight of KIO₃ in the reaction
$2 Cr (OH)_{3} + 4 OH + {KIO}_{3} ⟶ 2 {CrO}_{4}^{2 -} + 5 H_{2} O + KI is$

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a

Mole wt.

b

$\frac{Mol. wt.}{6}$

c

$\frac{Mol. wt.}{2}$

d

$\frac{Mol. wt.}{3}$

answer is A.

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Detailed Solution

$\frac{Molecular weight}{3} Because in {KIO}_{3} effective oxidation number is 3.$

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