The equivalent weight of MnSO₄ is half of its molecular weight when it is converted to

${\mathrm{MnSO}}_4\to {\mathrm{MnO}}_2+2{\mathrm{e}}^{-}$

Changes in the oxidation of Mn=2.

As a result, n-factor = 2.

Equivalent As a result, when MnSO₄ is converted to MnO₂, its equivalent weight is half of its molecular weight.