The equivalent weight of phosphoric acid H3PO4 in the reaction, NaOH+H3PO4→NaH2PO4+H2O is

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The equivalent weight of phosphoric acid $(H_{3} {PO}_{4})$ in the reaction, $NaOH + H_{3} {PO}_{4} \to {NaH}_{2} {PO}_{4} + H_{2} O$ is

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answer is D.

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Detailed Solution

$\begin{array}{ll} NaOH + H_{3} {PO}_{4} \to {NaH}_{2} {PO}_{4} + H_{2} O \begin{array}{l} 40 g 98 g \\ lmol 1 mol 1 g eq . \end{array} \end{array}$
Here 1 mole of NaOH reacts with 1 mole of $H_{3} {PO}_{4}$ Since substances react in the
ratio of their gram equivalents; thus, 1 g equivalent weight of NaOH reacts with 1 g
equivalent weight of $H_{3} {PO}_{4}$ . Therefore, equivalent weight of $H_{3} {PO}_{4}$ in this reaction is 98.