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Q.

The equivalent weight of ${CH}_{4}$ in the reaction ${CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O$ is

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a

$M/16$

b

$M/8$

c

$M/12$

d

$M/4$

answer is B.

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Detailed Solution

$\overset{- 4}{C} H_{4} + 2 O_{2} \to \overset{+4}{C} O_{2} + 2 H_{2} O$

Equivalent weight of ${CH}_{4} = \frac{M}{8}$

The carbon in methane has lost 8 electrons.

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