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Q.

The equivalent weight of ${KIO}_{3}$ in the reaction
$2 Cr {(OH)}_{3} + 4 {OH}^{-} + {KIO}_{3}^{} \to 2 {CrO}_{4}^{2 -} + 5 H_{2} O + KI$ is

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a

$\frac{Mol . wt .}{3}$

b

$\frac{Mol . wt .}{2}$

c

$\frac{Mol . wt .}{6}$

d

Molecular weight

answer is B.

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Detailed Solution

$K \overset{+ 5}{I} O_{3} \to K \overset{- 1}{I}; Change in Ox . state = 6$

$E_{{KIO}_{3}} = \frac{M}{6}$

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The equivalent weight of KIO3 in the reaction2CrOH3 + 4OH- + KIO3 → 2CrO42- + 5H2O + KI is