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The equivalent weight of ${MgCl}_{2} is$

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47.5

49.5

answer is D.

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Detailed Solution

Equivalent weight of ${MgCl}_{2} = \frac{Formula weight of {MgCl}_{2}}{Charge of cation or anion}$

In ${MgCl}_{2}$ ,there are one ${Mg}^{+ 2}$ and two - ${Cl}^{-}$ ions are present.

Then, the charge on cation ${Mg}^{+ 2} is 2$

The formula weight of ${MgCl}_{2} is 95 g .$

Therefore, Equivalent weight of ${MgCl}_{2} = \frac{95}{2} = 47.5$

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