The equivalent weights of ' $S$ ' in ${SCl}_2$ and $S_2{Cl}_2$ are in the ratio

equivalent weight $=\frac{atomicweight}{n -factor}$

here, n-factor refers to the charge on 'S' in respective compounds.

So, equivalent weight of sulphur in:

(i) ${SCl}_2$, equivalent weight $=\frac{32}{2}=16$

(ii) $S_2{Cl}_2$, equivalent weight $=\frac{32}{1}=32$

Ratio Obtained $\left({SCl}_2:S_2{Cl}_2\right)=16:32=1:2$ 

Hence, option (A) is correct.