The equvalent weight of iron in Fe₂O₃ would be 

 The compound, $\mathrm{F}{\mathrm{e}}_2{\mathrm{O}}_3$ is ferric oxide .In this compound  iron is present in +3 oxidation state. 

$\mathrm{Equivalent} \mathrm{weight} = \frac{\mathrm{Atomic} \mathrm{weight} }{\mathrm{n}-\mathrm{factor}}$

Therefore,

$\mathrm{Equivalent} \mathrm{weight} = \frac{56 }{3}=18.7$