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The error in the measurement of length of a simple pendulum is 0.1% and error in the time period is 2%. The possible maximum error in the quantity having dimensional formula LT^–2 is

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2.1%

4.1%

6.1%

1.1 %

answer is C.

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Detailed Solution

$\begin{array}{l} X = {LT}^{2} \Rightarrow \frac{ΔX}{X} = \frac{ΔL}{L} + 2 \frac{ΔT}{T} \\ % \frac{ΔX}{X} = 0.1 + 2 (2) = 0.1 + 4 = 4.1 % \end{array}$

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