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Q.

The escape velocity from earth is $v_{e} .$ A body is projected with velocity 2 $v_{e}$ . With what constant velocity will it move in the inter planetary space?

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a

$\sqrt{5} v_{e}$

b

$v_{e}$

c

$\sqrt{3} v_{e}$

d

$\sqrt{2} v_{e}$

answer is C.

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Detailed Solution

From conservation of energy, $\frac{1}{2} m {(2 v_{e})}^{2} = \frac{1}{2} {mv}_{e}^{2} + \frac{1}{2} m v^{2}$
From the above equation, we get: v = $\sqrt{3} v_{e}$

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