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The escape velocity of a body of mass 1 kg when projected from the surface of the earth is vertically is 11.2 km/s the escape velocity of a body of mass 2gm. When projected at an angle $60^{0}$ with the horizontal is

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$\frac{11.2}{2} k m / s$

$11.2 k m / s$

$11.2 \sqrt{2} k m / s$

$22.4 k m / s$

answer is B.

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Detailed Solution

$Escape velocity V_{e} = \sqrt{\frac{2 GM}{R}}, where M is mass of the plannet R is the radius of the plannet .$

So escape velocity is independent of mass of the body and angle of projection. Hence escape velocity does not change.

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