Q.

The escape velocity of a body on the earth’s surface is  Ve. A body is thrown vertically up with a speed of  kVe (where   k<1) . The maximum height reached by the body above the earth is (‘R’ is the radius of the earth)

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a

R(1k2k)

b

Rk2

c

R2k2(1k2)

d

R(k21k2)

answer is A.

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Detailed Solution

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vC=2GMR   

according to 2CE, 

-GMmR+12mv2=GMmR+h+0h=Rk21k2

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