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Q.

The escape velocity on earth is 11.2 km/s. On another planet having twice radius and 8 times mass of the earth, the escape velocity will be

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a

43.2 km/s

b

11.2 km/s

c

3.7 km/s

d

22.4 km/s

answer is C.

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Detailed Solution

$\frac{v_{p}}{v_{e}} = \sqrt{\frac{M_{p}}{M_{e}} \times \frac{R_{e}}{R_{p}}} = \sqrt{8 \times \frac{1}{2}} = 2$

$∴ v_{p} = 2 \times v_{e} = 22 .4 km / s$

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