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Q.

The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is:

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a

2

b

1

c

0.125

d

4

answer is C.

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Detailed Solution

Pex1=2Pex2⁡ or Pex1Pex2=21  Pex=4TrV1V2=r1r23=Pex2Pex13=123=18n=18=0.125 ∵ given V1=nV2

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