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The expanded form of $\log \frac{343}{125}$ is

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$3 (\log 7 + \log 5)$

$3 (\log 7 - \log 5)$

$3 (- \log 7 - \log 5)$

$3 (- \log 7 + \log 5) \frac{1}{4}$

answer is B.

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Detailed Solution

$\log_{a} \frac{x}{y} = \log_{a} x - \log_{a} y$

$\log \frac{343}{125} = \log 343 - \log 125$

$= \log 7^{3} - \log 5^{3}$

$\log_{a} x^{m} = m \log_{a} x = 3 \log 7 - 3 \log 5$

$\log \frac{343}{125} = 3 (\log 7 - \log 5)$

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