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Q.

The exponent of power of x  occurring in the 7th  term of expansion of (3x287x)9  is

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a

5

b

5

c

3

d

3

answer is B.

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Detailed Solution

Given expansion is(3x287x)9  

We have general term in the expansion (x+a)n

(Tr+1=nCrxnr(a)r be the expansion of (x+a)n)  

7th  term of expansion

T7=T6+1=9C6(3x2)96(87x)6

T7=T6+1=9C6(32)3(87)6x3  (xaxb=xab)  

The exponent of power of x  be the 3 (power of x )

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