The expression for the energy of electron in the hydrogen-like species is

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$- \frac{1}{n^{2}} [\frac{2 π^{2} m {(Z e^{2} / 4 π ε_{0})}^{2}}{h^{2}}]$

$\frac{1}{n^{2}} [\frac{2 π^{2} m {(Z e^{2} / 4 π ε_{0})}^{2}}{h^{2}}]$

$- \frac{1}{n^{2}} [\frac{2 π^{2} m h^{2}}{{(Z e^{2} / 4 π ε_{0})}^{2}}]$

$\frac{1}{n^{2}} [\frac{2 π^{2} m h^{2}}{{(Z e^{2} / 4 π ε_{0})}^{2}}]$

answer is B.

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Detailed Solution

$E_{n} =$ $- \frac{1}{n^{2}} [\frac{2 π^{2} m {(Z e^{2} / 4 π ε_{0})}^{2}}{h^{2}}]$ where m and e are the electron's mass and charge, and Z is the particle's atomic number.

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