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Q.

The expression relating mole fraction of solute in a solution with its molality is where the various symbols have their usual meanings.

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a

x2=1+mM1mρ

b

x2=1mM1mM1

c

x2=mM11+mM1

d

x2=mM11mM1

answer is C.

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Detailed Solution

Let W1 and M1 stand for the solvent's weight and molecular weight, respectively.
Molality m=n2W2

Therefore n2=mW1

x2=n2n1+n2=mW1W1M1+mW1=mM11+mM1

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