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The expression relating $μ / μ_{B}$ (whereµ is magnetic moment and $μ_{B}$ is Bohr magneton) with the number of unpaired electrons is

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$(μ / μ_{B}) = n$

$(μ / μ_{μ B}) = \sqrt{n (n + 1)}$

$(μ / μ_{B}) = \sqrt{n (n + 2)}$

$(μ / μ_{B}) = \sqrt{(n + 1) (n + 2)}$

answer is C.

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Detailed Solution

M = magoelic moment. of electron is an orbit

MB = Bohr magneton $\frac{^{'} e h}{4 Time}$

µ=iA

where, i= current = $- \frac{e v}{2 π r}$

= A = area of orbit

(mutiplying and dividing by me)

M = -e(merr)

M = -e 2 me R = тебя

-e h 2me 2TI 271

M= -neh 4π me

.: M = -neh 41 me -eh 4tme = n

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