Q.

The expression tanA1cotA+cotA1tanA can be written as

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a

sinAcosA+1

b

secAcosecA+1

c

secA+cosecA

d

tanA+cotA

answer is A.

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Detailed Solution

tanA1cotA+cotA1tanA

=tan2AtanA1+cotA1tanA

=1tanA1[tan2A1tanA]

=1tanA1[tan3A1tanA]

=(tan2A+1+tanA)(tanA)

=tanA+cotA+1

=sinAcosA+cosAsinA+1

=sin2A+cos2AcosAsinA+1

=1cosAsinA+1

=secAcosecA+1

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