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The extent of $π$ bonding order in M-0 is (M= central atom) :

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${BO}_{3}^{3 -} > {CO}_{3}^{2 -} > {NO}_{3}^{-}$

${CO}_{3}^{2 -} = {NO}_{3}^{-} = {BO}_{3}^{3 -}$

${CO}_{3}^{2 -} > {NO}_{3}^{-} > {BO}_{3}^{3 -}$

${NO}_{3}^{-} > {CO}_{3}^{2 -} > {BO}_{3}^{3 -}$

answer is B.

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Detailed Solution

Across the period, as size of $C.A.$ decreases tendency to form. $π$ bond increases.

The single bonds signify the presence of sigma bonds whereas the double bond indicates the presence of both sigma and pi bonds. Therefore we have 3 sigmas and 1 pi present here around the central C atom in carbonate i

Hence the extent of $π$ bonding order in M-0 is ${CO}_{3}^{2 -} > {NO}_{3}^{-} > {BO}_{3}^{3 -}$

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