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Q.

The external and internal diameters of a hollow cylinder are determined with vernier calipers and the result are recorded as $4.23 \pm 0.01 c m$ and $3.89 \pm 0.01 c m$ . The thickness of the cylinder wall within the limits of error is

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a

$0.34 \pm 0.04 c m$

b

$0.17 \pm 0.01 c m$

c

$0.34 \pm 0.02 c m$

d

$0.34 \pm 0.01 c m$

answer is B.

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Detailed Solution

Outer diameter $= 4.23 \pm 0.01$

Inner diameter $= 3.89 \pm 0.01$

Thickness $4.23 - 3.89 \pm (0.01 + 0.01)$

$= 0.34 \pm 0.02$

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The external and internal diameters of a hollow cylinder are determined with vernier calipers and the result are recorded as 4.23±0.01cm and 3.89±0.01cm . The thickness of the cylinder wall within the limits of error is