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Q.

The external diameter of a 5m long hollow tube is 10 cm and the thickness of it is 5 mm. The specific resistance of copper is 1.7×10−5 Ωm , then its resistance is  

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a

5.7×10−5 Ωm

b

6.7×10−5 Ωm

c

0.057 Ω

d

0.67×10−5 Ωm

answer is D.

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Detailed Solution

R=ρlπ(R22−R12)=1.7×10−5×53.14[(0.05)2−(0.045)2]=0.057Ω
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