The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea (7.8 mm). This surface separates two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus

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3.1 cm

4.0 cm

1 cm

2 cm

answer is C.

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Detailed Solution

Using refraction formula, $\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
or $\frac{1 .34}{f} - \frac{μ_{1}}{\infty} = \frac{1 .34 - 1}{7 .8} = \frac{3 .4}{78}$

$f = \frac{1.34 \times 78}{3.4} = 30.7 mm ≃ 3.1 cm$

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